To sort the array having binary numbers i.e. 0 & 1 only

public class BinarySort {

 public static void main(String[] args) {
  
  long start = System.nanoTime();
  byte[] array = {0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 0, 1, 1, 1, 0};
  byte temp = 0;
  for(int i = 0; i < array.length; i++){
   if(i == 0)
    continue;
   if(array[i-1] == 1 && array[i] == 0){
    for(int j = i; j > 0; j--){
//     Below if block makes the loop shorter & execute the code twice faster
     if(array[j-1] == 0)
      break;
     temp = array[j-1];
     array[j-1] = array[j];
     array[j] = temp;
    }
   }
  }
  for(int i = 0; i < array.length; i++){
//   System.out.println(array[i]);
  }
  System.out.println(System.nanoTime() - start);
 }
}